Steps to change the RSA Authentication API 8.x Output Return Statements in the Sample Code

[#1]

Article Number

000039291

Applies To

RSA Product Set: RSA SecurID
RSA Product/Service Type: Authentication Agent API
RSA Version/Condition: 8.x

Issue

When running the sample code for the RSA Authentication API 8.x, The statements that are returned after you start the Authentication looks like follows:

• In case of an Authentication Failure:

Access Denied

• In New Pin Mode:

New Pin accepted; please login again with the new Pin.

• In case of a successful authentication:

Passcode Accepted
Authentication successful

Some customers use the Sample Code that is provided as it is, so they just need to customize the Output coming from the Sample Code.

Resolution

After downloading the .zip file for any 8.x RSA Authentication API from here:

1. Extract the folder, then go to examples then sample.
2. Edit the file that is called \examples/sample\AuthUser.java in the extracted folder, this is the file that the Sample Code runs and it contains the main method. 
3. At the very first beginning of the file, you will see all the return values being initialized, you can change it to whatever you need.

private static final String ACCESS_DENIED = "Access Denied";

private static final String PASSCODE_ACCEPTED = "Passcode Accepted";

private static final String PIN_REJECTED = "New Pin rejected";

private static final String PIN_ACCEPTED = "New Pin accepted; please login again with the new Pin.";

private static final String GOOD_AUTH = "Authentication successful";

private static final String BAD_AUTH = "Authentication incomplete";

4. Do not forget to Save the File.